Express 2.36 bar + 0.23 bar in the form of p upon q where p and q are integers and q is not equal to zero
Answers
Answered by
59
2.36 bar = 2.3636
100 x = 236.3636
100 x - x = 234
99 x = 234
x = 234/99 = 78/33 = 26/11
0.23 bar = 0.2323
100 x = 23.2323
100 x - x = 23
99 x = 23
x = 23/99
26/11+23/99=234+23/99=257/99
100 x = 236.3636
100 x - x = 234
99 x = 234
x = 234/99 = 78/33 = 26/11
0.23 bar = 0.2323
100 x = 23.2323
100 x - x = 23
99 x = 23
x = 23/99
26/11+23/99=234+23/99=257/99
Answered by
8
2.36 bar = 2.3636
100 x = 236.3636
100 x - x = 234
99 x = 234
x = 234/99 = 78/33 = 26/11
0.23 bar = 0.2323
100 x = 23.2323
100 x - x = 23
99 x = 23
x = 23/99
26/11+23/99=234+23/99=257/99
pls mark brainiest
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