express 2+3i/2-3i in a+ib form
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Step-by-step explanation:
firstly rationalize the whole term by multiplying 2+3i in Numerator and denominator .
therefore (2+3i)^2/4+9 [since i^2 =-1 in denominator the formula will be (a-b)(a+b) = a^2-b^2]
4-9+12i/13
in a+ib form it will be -5/13+12i/13
in which a = -5/13 & b= 12/13
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