Question

express 2+i/(3-i)(1+2i) in a+ib​

Answer 1

Answer:

Given : 2+i/(3-i) (1+2i)

2+i/3(1+2i) -i(1+2i)

$2 + i \div 3 + 6i - i + {2i}^{2}$

2+i/3+5i+2(-1)....isquare =√-1

2+i/3+5i-2

2+i/1+5i

2+i/1+5i ×1-5i/1-5i

(2+i)(1-5i) /1 square - 5i square

2(1-5i) +i(1-5i) /1-25i square

2-10i+i-5i square/1+25.... I square=√-1

2-9i+5/26

7-9i/26

=a+ib

Answer 2

Answer:

Step-by-step explanation: