Question

Express 21^2as the sum of two consecutive number​

Answer 1

please mark it as brainliest

Answer 2

Answer:

220 and 221

solution

let the 2 consecutive no.s be x and (x + 1)

${21}^{2} = 441 \\ \\ = > 441 = x + x + 1 \\ = > 441 = 2x + 1 \\ = > 440 =2x \\ = > 220 = x \\ \\ therefore \: \\ {21}^{2} = 441 = 220 + 221$