Question

Express 216 as a product of prime factores

Answer 1

Hey mate!!

Here's your answer

Prime factorization: 216 = 2 x 2 x 2 x 3 x 3 x 3, which can be written 216 = 2^3 x 3^3.

The exponents in the prime factorization are 3 and 3.

Adding one to each and multiplying we get (3 + 1) x (3 + 1) = 4 x 4 = 16. Therefore 216 has 16 factors.

Hope it helped you.......Mark me as brainliest.....

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

$\\ \\ \Large{ \begin{array}{c|c} \tt 2 & \sf{216} \\ \cline{1-2} \tt 2 & \sf {108} \\ \cline{1-2} \tt 2 & \sf{54} \\ \cline{1-2} \tt 3 & \sf{27 }\\ \cline{1-2} \tt 3 & \sf{ 9 }\\ \cline{1-2} \tt 3 & \sf{3} \\ \cline{1-2} & \sf{ 1} \end{array}} \\ \\ \implies 216 = 2*2*2*3*3*3 \\ \implies 216 = 2^3*3^3. \\ \\ \\ HOPE\:IT\:HELPS!!!!!!$