Question

express 21square as sum of 2 consecutive integers

Answer 1

Dear Friend,
(21)^2=441
1st consecutive number be x.
2nd number =(x+1)
x+x+1=441
2x=441-1
x=440/2
x=220
2nd number=220+1=221
so, answer are 220 and 221.
hope it helps u.

Answer 2

Answer:

The sum of two consecutive integers of $21^{2}=220+221$

Step-by-step explanation:

This is because initially $21^{2}=441$

Let the two consecutive numbers be taken as x and x+1  

Now, x+x+1 = 441

On solving we get,

⇒2x+1=441  

⇒2x=440⇒x=220  

Thus, x=220 and x+1 = 221  

In this case since 21 is an odd number it can be written as a sum of two consecutive numbers. Suppose the number was an even number it cannot be written as the same.