Express 21square as the sum of two consecutive numbers
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Answered by
3
Define x:
Let one number be x
The other consecutive number = x + 1
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Sum of 2 consecutive numbers = 21²:
x + (x + 1) = 21²
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Solve x:
x + (x + 1) = 21²
Open bracket and evaluate 21²:
x + x + 1 = 441
Combine like terms:
2x + 1 = 441
Take away 1 from both sides:
2x = 440
Divide both side by 2:
x = 220
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Find the two numbers:
one number = x = 220
the other number = x + 1 = 220 + 1 = 221
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Answer: The two numbers are 220 and 221.
devanandasaju999:
Nice work bro!!!
Answered by
1
21 sqare =441. Two consecutive numbers are
x+1 and x+2
x+1+x+2=441
2x+3=441
2x=441-3
2x=438
x=438÷2
x=219
x+1=219+1=220
x+2=219+2=221
x+1 and x+2
x+1+x+2=441
2x+3=441
2x=441-3
2x=438
x=438÷2
x=219
x+1=219+1=220
x+2=219+2=221
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