Question

express 22/222 in its standard from​

Answer 1

Answer:

here the answer  hope it is clear  :)

Step-by-step explanation:

If you take powers of 2, the last digit cycles through 2 -> 4 -> 8 -> 6 -> 2 etc. so there is a cycle of length 4.

((2^22)^222)^22222 = 2^(22.222.2222) = 2^k for a k that equals 0 (mod 4). SO, it ends in 6.

However, the same question for 2^(22^(222^2222)) is more difficult, because we have to look at the exponent first and find where 22^(222^2222) ends in the 4-cycle? Well, that requires that look at the last 2 digits of 222^2222, and it is more complicated.

The first case is the standard interpretation of your expression, since we read from left to right and there is only exponentiation.

Answer 2

Answer:

Step-by-step explanation:

22/222

11/111