Question

Express 225 as sum of odd consecutive natural numbers.​

Answer 1

Let x be an odd integer, For simplicity (see further below)* set the first 5 consecutive odd integers to be:

x-4, x-2, x, x+2, x+4

We know that the sum of these is 225

=> 5x = 225 ( x-4 + x-2 + x + x+2 + x+4 = 5x)*

=> x = 225/5

=> x = 45

So, the numbers are: 45-4, 45-2, 45, 45+2, 45+4 = 41, 43, 45, 47, 49

Hence the sum i(in this case) of the next five odd numbers =

51+53+55+57+59

= 275

Answer 2

Answer:

I am giving here three consecutive odd numbers

Step-by-step explanation:

let x be the first natural number

then,

second natural number= x+2

third natural number= x+4

A.T.Q(According To Question)

x+x+2+x+4= 225

3x+6= 225

3x= 225-6

3x= 219

x= 219/3

x= 73

therefore,

first natural number= 73

second natural number= x+2= 73+2= 75

third natural number= x+4= 73+4= 77

numbers are= 73,75,77