Math, asked by yaashar, 3 months ago

Express 2520 as product of prime factors.​

Answers

Answered by ItzRudaina
1

Here are the first several prime factors: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29...

Let's start by dividing 2,520 by 2

2,520 ÷ 2 = 1,260 - No remainder! 2 is one of the factors!

1,260 ÷ 2 = 630 - No remainder! 2 is one of the factors!

630 ÷ 2 = 315 - No remainder! 2 is one of the factors!

315 ÷ 2 = 157.5 - There is a remainder. We can't divide by 2 evenly anymore. Let's try the next prime number

315 ÷ 3 = 105 - No remainder! 3 is one of the factors!

105 ÷ 3 = 35 - No remainder! 3 is one of the factors!

35 ÷ 3 = 11.6667 - There is a remainder. We can't divide by 3 evenly anymore. Let's try the next prime number

35 ÷ 5 = 7 - No remainder! 5 is one of the factors!

7 ÷ 5 = 1.4 - There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number

7 ÷ 7 = 1 - No remainder! 7 is one of the factors!

The divisor(s) above are the prime factors of the number 2,520. If we put all of it together we have the factors 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2,520. It can also be written in exponential form as 23 x 32 x 51 x 71.

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