Question

Express 29 as difference of the square of two consecutive numbers

Answer 1

Answer:

14,15

Step-by-step explanation:

(n+1)^2-n^2=29

(n+1+n)(n+1-n)=29

2n+1=29

n=14

Answer 2

Answer

Let the numbers be = a, a + 1

Difference of squares:

(a+1)^2 - a^2 = 29

=> a^2 + 1 + 2a - a^2 = 29

=> 2a + 1 = 29

=> 2a = 28

=> a = 14

=> a + 1 = 15