Question

Express
2log a+3log b as single logarithm

Answer 1

Answer:

$2loga+3logb=log\:(a^{2}\times b^{3})$

Step-by-step explanation:

$2loga+3logb\\=loga^{2}+logb^{3}$

$\boxed {nlogm = logm^{n}}$

$=log\:(a^{2}\times b^{3})$

$\boxed {logm+logn = log\:(mn)}$

Therefore,

$2loga+3logb=log\:(a^{2}\times b^{3})$

•••♪

Answer 2

Answer:

Step-by-step explanation: