Express 2log3-1/2log16+log12 as a single logarithim
Answers
Answered by
1
Answer:
2log3−1/2log16+log12
Let simplify the expressions into single logarithm,
2log3−1/2log16+log12=2log3−
1/2
log4
2
+log12
=2log3−log4+log12
=log3
2
−log4+log12
=log(9×12)/4
=log(9×3)
=log27
Similar questions
Math,
2 months ago
Environmental Sciences,
2 months ago
English,
2 months ago
Social Sciences,
1 year ago
Chemistry,
1 year ago