Question

Express 2log3-1/2log16+log12 as a single logarithim

Answer 1

Answer:

2log3−1/2log16+log12

Let simplify the expressions into single logarithm,

2log3−1/2log16+log12=2log3−

1/2

log4

2

+log12

=2log3−log4+log12

=log3

2

−log4+log12

=log(9×12)/4

=log(9×3)

=log27