Question

express √3+1/2√2-√3 with rational denominator

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{ \sqrt{3} + 1 }{2 \sqrt{2} - \sqrt{3} } \\ \\ on \: rationalizing \: we \: get \\ \\ = \frac{ \sqrt{3} + 1}{2 \sqrt{2} - \sqrt{3} } \times \frac{2 \sqrt{2} + \sqrt{3} }{2 \sqrt{2} + \sqrt{3} } \\ \\ = \frac{ \sqrt{3} \times 2 \sqrt{2} + \sqrt{3} \times \sqrt{3} + 1 \times 2 \sqrt{2} +1 \times \sqrt{3} }{ {(2 \sqrt{2} ) }^{2} - {( \sqrt{3} )}^{2} } \\ \\ = \frac{2 \sqrt{6} + 3 + 2 \sqrt{2} + \sqrt{3} }{8 - 3} \\ \\ = \frac{3 + 2 \sqrt{2} + \sqrt{3} + 2 \sqrt{6} }{5}$

Hope this helps!!!

@Mahak24

Thanks...
☺

Answer 2

thank you so much for your answer