express 3+2√5/3-2√5 into the form of a number having denominator as an intger
ajitss:
anyone knows the ans pls help
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=( (3+2^1/2×5)×(3+2^1/2×5) )/( (3-2^1/2×5) ×(3+2^1/2×5) )
=(3+2^1/2×5)^2/( (3)^2-(2^1/2×5)^2)
=(9+20+6+4^1/2×5)/(9-20)
=(35+4^1/2×5)/(-11)
=-(35+4^1/2)/11
=(3+2^1/2×5)^2/( (3)^2-(2^1/2×5)^2)
=(9+20+6+4^1/2×5)/(9-20)
=(35+4^1/2×5)/(-11)
=-(35+4^1/2)/11
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