Express √3 cosx + sinx in the form of R sin(x+infinity)
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Answer:
Step-by-step explanation:
cosx+3–√sinx=2cos(x−60∘)=2–√
So, cos(x−60∘)=12√=cos45∘
⟹x−60∘=n360∘±45∘ where n is any integer
Taking ′+′ sign, x−60∘=n360∘+45∘⟹x=n360∘+105∘
If 0≤x≤360∘,0≤n360∘+105∘≤360∘⟹n=0
Taking ′−′ sign, x−60∘=n360∘−45∘⟹x=n360∘+15∘
If 0≤x≤360∘,0≤n360∘+15∘≤360∘⟹n=0
So, x=15∘,105∘
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