express (3+ i√2)(3- i√2)/(5+2i)-(5+2i) in the form of a + ib
Answers
Answered by
7
Answer is Infinite
Because
We Guess A=(3) & B={(2)^1/2i}Then (A+B)(A-B)=[(A)^2-(B)^2]
Numerator is [(3)^2-{(2)^1/2i}^2]=11
& Denometer is (5+2i)-(5+2i)=0
Then (Numerator/Denometer)= (11/0)=Infinite
Because
We Guess A=(3) & B={(2)^1/2i}Then (A+B)(A-B)=[(A)^2-(B)^2]
Numerator is [(3)^2-{(2)^1/2i}^2]=11
& Denometer is (5+2i)-(5+2i)=0
Then (Numerator/Denometer)= (11/0)=Infinite
Similar questions