Question

Express 36 as the sum of first n odd number

Answer 1

1,3,5,7,9......

first term, a = 1

common difference, d = 2

Sn = 36

Sn = n/2 [ 2 ( a ) + ( n – 1 ) × d ]

36 = n/2 [ 2 ( 1 ) + ( n – 1 ) × 2 ]

36 = n/2 [ 2 + 2n – 2 ]

36 × 2 = n × 2n

36 = n²

n = √36

n = 6

Hence 36 = 1 + 3 + 5 + 7 + 9 + 11

Answer 2

Step-by-step explanation:

1=1

1+3=4

1+3+5=9

1+3+5+7=16

1+3+5+7+9=25

1+3+5+7+9+11=36

Therefore, 36 can be expressed as the sum of first 6 odd numbers.