Question

Express 3log 2 base 2 =x in exponential form

Answer 1

Answer:

2^3=2^x

Step-by-step explanation:

3log2base2=log2^3base2=x

So, 2^x=2^3.

Answer 2

The value of$3\log _2 2=x$ in exponential form is$2^{x} =2^{3}$

Step-by-step explanation:

We have,

$3\log _2 2=x$

⇒$\log _2 2^{3} =x$

[Since, $m\log a= \log a^{m}$]

⇒$2^{3} =2^{x}$

[Since, $\log_ax= b ,a^{b} =x$]

$2^{x} =2^{3}$

Hence, the value of$3\log _2 2=x$ in exponential form is $2^{x} =2^{3}$.