Question

Express √48 in the form n√3, where n is an integer.

Answer 1

$\sqrt{48} = \sqrt{2 * 2 *2 * 2* 3}$ = $\sqrt{4 * 4 * 3}$ = $4 * \sqrt{3}$ = $4\sqrt{3}$

{ an expression in the form  $\sqrt{A * A * B}$ can be written is $A * \sqrt{B}$ = $A\sqrt{B}$}

then $\sqrt{48} = 4\sqrt{3}$

n = 4 so, $n\sqrt{3} = 4\sqrt{3}$.

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