Question

express 49 as sum of odd numbers

Answer 1

As we know that the sum of first n odd natural numbers is n2

49=(7)2

49 is the sum of first 7 odd natural numbers.

49=1+3+5+7+9+11+13

$hope \: it \: will \: help \: you$

Answer 2

Answer:

49 as a sum of odd numbers is $(1 + 3 + 5 + 7 + 9 + 11 + 13)$

Step-by-step explanation:

Here given number is 49.

We want to find 49 as sum of odd numbers.

Easily we can find it.

But before solving this question we should know what is odd number ?

Odd number is a number which is not divisible by 2.

For example,1,3,5,7,.....e.t.c.

Now,

$49 = 1 + 48 \\ = 1 + 3 + 45 \\ = 1 + 3 + 5 + 40 \\ = 1 + 3 + 5 + 7 + 33 \\ = 1 + 3 + 5 + 7 + 9 + 24 \\ = 1 + 3 + 5 + 7 + 9 + 11 + 13$

This is a problem of Algebra.

Some important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)