Question

Express 49 as the sum of 7 odd numbers

Answer 1

The 7 odd numbers would be n + (n+2) + (n+4) + (n+6) + (n+8) + (n+10) +(n+12).< Where n is an odd number. ;Add them will equal 7n + 42 = 49
7n = 7
n = 1
So the numbers will be 1, 3, 5, 7, 9, 11, 13.

Answer 2

Heya!!
Thanks for asking the question.
Here is your answer:-
We have to express 49 as the sum of 7 odd numbers .
As we know 1 is square of 1,
1+3 is square of 2,
1+3+5 is square of 3,
1+3+5+7 is square of 4,
1+3+5+7+9 is square of 5,
1+3+5+7+9+11 is square of 6,
and so on........
Here we can observe that :-
Sum of first n odd numbers = n^2

So 49 can be expressed as the sum of first 7 odd numbers,
1+3+5+7+9+11+13 is square of 7 i.e. 49.

Hope it helps you.