Math, asked by sangk6422, 1 year ago

Express 5.12bar in the form of p/q













































































kartikeya905: It can be expressed as:-
Let x=5.12bar ———-(i)
Now take 5.12bar equals to
x=5.1212bar
Then multiply both the sides by 100 because bar is on two numbers ‘1’ and ‘2’.
So we have 100x=512.12bar ———-(ii)
Now subtract eq. (i) form (ii)
100x-x=512.12bar-5.12bar
99x=507
x=507/99
x=169/33 Ans.
Happy to help
kartikeya905: It can be expressed as:-
Let x=5.12bar ———-(i)
Now take 5.12bar equals to
x=5.1212bar
Then multiply both the sides by 100 because bar is on two numbers ‘1’ and ‘2’.
So we have 100x=512.12bar ———-(ii)
Now subtract eq. (i) form (ii)
100x-x=512.12bar-5.12bar
99x=507
x=507/99
x=169/33
kartikeya905: It can be expressed as:-
Let x=5.12bar ———-(i)
Now take 5.12bar equals to
x=5.1212bar
Then multiply both the sides by 100 because bar is on two numbers ‘1’ and ‘2’.
So we have 100x=512.12bar ———-(ii)
Now subtract eq. (i) form (ii)
100x-x=512.12bar-5.12bar
99x=507
x=507/99
x=169/33
Happy to help
kartikeya905: It can be expressed as:-
Let x=5.12bar ———-(i)
Now take 5.12bar equals to
x=5.1212bar
Then multiply both the sides by 100 because bar is on two numbers ‘1’ and ‘2’.
So we have 100x=512.12bar ———-(ii)
Now subtract eq. (i) form (ii)
100x-x=512.12bar-5.12bar
99x=507
x=507/99
x=169/33
Happy to help

Answers

Answered by Anonymous
16
\underline{\mathfrak{\huge{The\:Question:}}}

Express \tt{5.\overline{12}} in the form of \tt{\frac{p}{q}}\\

\underline{\mathfrak{\huge{Here's \:Your\:Answer:}}}

Let :

\tt{5.\overline{12} = x} [ Let this be equation (1) ]

Multiply this formed equation by 100 ( × 100 )

\tt{5.\overline{12} \times 100 = x \times 100}

Solve this equation further

\tt{512.\overline{12} = 100x} [ Let this be equation (2) ]

Now, subtract equation (1) from equation (2) :

\tt{512.\overline{12} - 5.\overline{12} = 100x - x}

Solve this formed equation further

\tt{507 = 99x}

Take 99 on the other hand side and then find the value of x by solving the formed equation further

\tt{x = \frac{507}{99}}\\

There you got the value of \tt{5.\overline{12}}.
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