Question

express 68 and 128 as the sum of two consecutive prime​

Answer 1

Answer:

$68=(2*16+1)+(2*16+3)=33+35=68\\128=(2*31+1)+(2*31+3)=63+65=128$

Step-by-step explanation:

There are two numbers $68$ and $128$ which are expresses  as the sum of two consecutive prime are as shown below one by one:

$68=(2*16+1)+(2*16+3)=33+35=68\\128=(2*31+1)+(2*31+3)=63+65=128$

So,these are the sum of two consecutive prime.

Answer 2

Consecutive prime numbers:

The prime numbers which lie on real line consecutively are consecutive prime numbers. The prime numbers 2, 3 are consecutive but the prime numbers 3 and 7 are not consecutive because there is another prime number 5 lying between them.

Step-by-step explanation:

1.

First number is (a) = 68

Now a/2 = 34

So the consecutive prime numbers added as the sum 68 must attain values nearing to 34.

The prime numbers close to 34 are 29, 31, 37, 41

We have 68 = 31 + 37

2.

Second number is (a) = 128

Now a/2 = 64

So the consecutive prime numbers added as the sum 128 must attain values nearing to 64.

The prime numbers close to 64 are 59, 61, 67, 71.

We have 128 = 61 + 67