Math, asked by kaushik000011, 7 months ago

express 6log2+4log3+2log5 in simplified form​

Answers

Answered by mm4453418
0

l can't answer sorry but I will help you next time

Answered by pulakmath007
11

SOLUTION

TO EXPRESS

 \sf{}6   \log 2+ 4 \log 3 + 2 \log 5

in simplified form

FORMULA TO BE IMPLEMENTED

  \sf{} 1. \:  \:  \:  \log (ab) =  \log a+  \log b

 \sf{}2. \:  \:    \log  ({x}^{m} ) =  m \log x

EVALUATION

 \sf{}6   \log 2+ 4 \log 3 + 2 \log 5

 =   \sf{} \log ( {2}^{6} )+ \log ( {3}^{4} )+  \log ( {5}^{2} ) \:  (\: by \: formula \: 2)

 =   \sf{} \log 64+ \log 81+  \log 25

 =   \sf{} \log ( 4 \times 16 )+ \log 81+  \log 25 \:

 =   \sf{} \log 16 +  \log 4+ \log 81+  \log 25 \:  (by \: formula \: 2)

 =   \sf{} \log 16 + \log 81+  \log 4   + \log 25 \:

 =   \sf{} \log (16   \times 81)+  \log( 4    \times  25) \:

 =   \sf{} \log  {(2 \times 3)}^{4} +  \log( {10}^{2} ) \:

 =   \sf{}4 \log  (2 \times 3) + 2 \log( {10}) \:

 =   \sf{}4 \log  6 + 2  \:  \: ( \because \: \log  10 = 1)

FINAL ANSWER

 \sf{}6   \log 2+ 4 \log 3 + 2 \log 5 = 4 \log 6 + 2

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