Question

Express 6raise to power 3 in sum of consecutive odd no.

Answer 1

Answer:

31+33+35+37+39+41

Step-by-step explanation:

We know,

1=1=1

3+5=8=2^3

7+9+11=27=3^3

13+15+17+19=64=4^3

21+23+25+27+29=125=5^3

31+33+35+37+39+41=216=6^3

Therefore, the sum of odd consecutive cube number for 6^3=216 must be 31+33+35+37+39+41.