Math, asked by prabhleenkpanesar, 6 months ago

express 6sq as a sum of consecutive odd no.

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Answered by bhavanij0705
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To find : Express 6 square as the sum of consecutive odd numbers ?

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+13

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+17

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+1736= 3 + 5 + 11 + 1736=3+5+11+17

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+1736= 3 + 5 + 11 + 1736=3+5+11+1736= 3 + 5 + 13 + 1536=3+5+13+15

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+1736= 3 + 5 + 11 + 1736=3+5+11+1736= 3 + 5 + 13 + 1536=3+5+13+1536= 1 + 7 + 13 + 1536=1+7+13+15

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+1736= 3 + 5 + 11 + 1736=3+5+11+1736= 3 + 5 + 13 + 1536=3+5+13+1536= 1 + 7 + 13 + 1536=1+7+13+15#Learn more

To find : Express 6 square as the sum of consecutive odd numbers ?Solution :Square of 6 is 6^2=366 2 =36The consecutive odd numbers are 1,3,5,7,9,11,13,15,17,19,23,29,31,...Now, we write the sum of consecutive odd numbers as36 = 5 + 7 + 11 + 1336=5+7+11+1336= 1 + 3 + 15 + 1736=1+3+15+1736= 3 + 5 + 11 + 1736=3+5+11+1736= 3 + 5 + 13 + 1536=3+5+13+1536= 1 + 7 + 13 + 1536=1+7+13+15#Learn moreExpress 1331 as the sum of consecutive odd numbers

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