Question

Express 7i^7 + 7i^6 + 3i^3 – 2i^2 + 1 in the form of a + bi​

Answer 1

Answer:

(-10i-3)=(-10i-3

Step-by-step explanation:

______Here is answer______

7 {i}^{7} + 6 {i}^{6} + 3 {i}^{3} - 2 {i}^{2} + 17i

7+6i 6+3i 3−2i 2+1

= 7 {i}^{(4 + 3)} + 6 {i}^{(4 + 2)} + 3 {i}^{3} - 2 {i}^{2} + 1=7i (4+3) +6i 4+2)+3i 3−2i 2+1

= 7 ( - i) + 6( - 1) + 3( - i) - 2( - 1) + 1=7(−i)+6(−1)+3(−

i−2(−1)+1

= - 7i - 6 - 3i + 2 + 1=−7i−6−3i+2+1

= ( - 10i - 3)=(−10i−3)

Hope its help u

Answer 2

Answer:

sorrry i dont know

Step-by-step explanation: