Question

express 8871.12/990 in p/q form where q≠0​

Answer 1

Answer:

887112/99000

Step-by-step explanation:

I thought that this will help you

Answer 2

Answer:

I am giving u ans of other problem . you try yourself by seeing this.

Step-by-step explanation:

Given a number 0.2353535…….

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zero

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,99x=23.53535…−0.2353535…

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,99x=23.53535…−0.2353535…x= 23.33 / 99

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,99x=23.53535…−0.2353535…x= 23.33 / 99x= 233/ 990

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,99x=23.53535…−0.2353535…x= 23.33 / 99x= 233/ 990Hence, x=0.2353535…=0.235‾ can be expressed in the form of p/q as 233/ 990 and here q=990 (q≠zero)

Given a number 0.2353535…….We need to prove0.2353535…= 0.235‾can be expressed in the form of p/q, where p and q are integers and q ≠zeroProof:Let us assume that x=0.2353535…=0.235 ——————(i)On Multiplying both sides by 100 of equation (i) we get,100x=100×0.2353535…100x=23.53535————–(ii)Subtracting equation (i) from equation (ii) we get,99x=23.53535…−0.2353535…x= 23.33 / 99x= 233/ 990Hence, x=0.2353535…=0.235‾ can be expressed in the form of p/q as 233/ 990 and here q=990 (q≠zero)Hence proved