Question

express 9 square as the sum of two cosecutive integers​

Answer 1

Answer:

9^2=81 so two consecutive integers be (4+5)^2=4^2+5^2+2×4×5=16+25+40

81 solved

Answer 2

Answer:

The Integers would be 40 and 41

Step-by-step explanation:

let the numbers be x and x + 1

$x + x + 1 = { 9}^{2} \\ = )2x + 1 = 81 \\ = )2x = 80 \\ = )x = 40$

So The Numbers are :-

x = 40

=)x + 1 =40 + 1

=)41

So it can be expressed as :-

40 + 41 = 9²

=)40 + 41 = 81

Hope it helped