Question

Express a square + 7 x + 12 by X square + 2 x minus 3 into lowest term

Answer 1

$\red{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Express a square + 7 x + 12 by X square + 2 x minus 3 into lowest term

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$( {a}^{2} + 7x + 12)( {x}^{2} + 2x - 3)$

${a}^{2} {x}^{2} 2 {a}^{2} x - 3 {a}^{2} + 7 {x}^{3} + 14 {x}^{2} - 21x + 12 {x}^{2} + 24x - 36$

${a}^{2} (2 {x}^{3} - 3) + 7x( {x}^{2} + 2x - 3) + 12( {x}^{2} + 2x - 3)$

$( {a}^{2} + 7x + 12)(2 {x}^{3} - 3)x {x}^{2} + 7x - 3)( {x}^{2} + 2x - 3)$

Here is your answer^^^^^

see in the picture above attach for complete solution step by step:-

Hope it helps you..!!!

_________________

Thankyou:)