Math, asked by hemavathiacharya123, 5 days ago

express all the trigonometric ratios in terms of sin x​

Answers

Answered by jebasania786
0

the trigonometric ratios in terms of sin x are =

Hope it helps u

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Answered by Dimpi04
0

Answer:

For cos x---

cos² x + sin²x = 1

=> cos² x = 1 - sin²x

=> cos x = √(1 - sin²x) ------------(I)

for tanx---

tan x = sin x/ cos x

= sin x/√(1 - sin²x) { from (I) }---------(ii)

for cot x----

cot x = 1/ tan x

=1/{sin x/√(1 - sin²x } { from (ii) }

=√(1 - sin²x) /sin x

For sec x------

sec x = 1/cos x

= 1/√(1 - sin²x) {from (I) }

for cosec x------

cosec x = 1/ sin x

This☝is the correct answer

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