express all the trigonometric ratios in terms of sin x
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the trigonometric ratios in terms of sin x are =
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Answer:
For cos x---
cos² x + sin²x = 1
=> cos² x = 1 - sin²x
=> cos x = √(1 - sin²x) ------------(I)
for tanx---
tan x = sin x/ cos x
= sin x/√(1 - sin²x) { from (I) }---------(ii)
for cot x----
cot x = 1/ tan x
=1/{sin x/√(1 - sin²x } { from (ii) }
=√(1 - sin²x) /sin x
For sec x------
sec x = 1/cos x
= 1/√(1 - sin²x) {from (I) }
for cosec x------
cosec x = 1/ sin x
This☝is the correct answer
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