Express(alpha+I bita)holes to the power I in the form A+iB?
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rijwanabano123:
Ans is e to the power -(2npi+theta). Into ( cos (logr)+isin(logr))
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HEY FRIEND HERE YOUR ANSWER
(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS....
(1-i)^4
{(1-i)^2}^2
{(1+i^2-2i)}^2
{(1-1-2i)}^2
(-2i)^2
4i^2
(-4)=-4+0i
where a=-4 and b=0
>>this is in the form of a+ib where
a is equal to-4
●●and●●
b is equal to 0
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS....
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