Express as a perfect square with the help of a formula and then find the value of÷
(a). 9(a+b)²-6(a+b)c+c²,then a =5,b=(-7) and c=11
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ANSWER:
289
Step-by-step explanation:
9{5+(-7)}^2 -6{5+(-7)}11 + 11^2 [substituting values]
9(-2)^2 -6(-2)11 + 121 [solving brackets]
9*4 -6*-22 +121 [ *=multiply] [x^2/-x^2=x^2(square of both x and -x results in x^2) take an example x=2 . If we multiply 2*2=4 , -2*-2=4]
36 +132 +121 [- * - = +] (rules of BODMAS) [B=bracket , O=of , D=divide , M=multiply , A=addition , S= subtraction ]
=289
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