Question

Express complex number in the form a + ib. ​

Answer 1

Answer: 0+i0

Step-by-step explanation:

We know that,

in $a+ib$, $a$ represents real part while $ib$ represents the imaginary part.

Also,

$i^{2}=-1$

So,

$i^{9}+i^{19}$  can be written as,

$=i*i^{8} +i*i^{18}$

$=i*(i^{2})^{4} +i*(i^{2} )^{9}$                              $\left[ as,\\a^{mn} = (a^{m})^{n} ]$

Putting $i^{2}=-1$,

$=i*(-1)^{4}+i*(-1)^{9}$

$=i*1+i*(-1)$

$=i-i$

$=0$

Therefore,

$0+i0$ is the required answer.