Express cos 68° + tan 76° in terms of angles between 0 & 45
Answers
Answered by
19
Step-by-step explanation:
Given:-
cos 68° + tan 76°
To find:-
Express cos 68° + tan 76° in terms of angles between 0° & 45°
Solution:-
Given that : cos 68° + tan 76°
It can be written as
Cos (90°-22°) + Tan (90°- 14°)
We know that
Cos (90°-A) = Sin A
Tan (90°-A) = Cot A
So ,
Cos (90°-22°)= Sin 22°
Tan (90°-14°) = Cot 14°
Cos (90°-22°) + Tan (90°- 14°)
=>Sin 22° + Tan 14°
Answer:-
Cos 68°+ Tan 76° = Sin 22° + Cot 14°
Used formulae:-
- Cos (90°-A) = Sin A
- Tan (90°-A) = Cot A
Answered by
10
Step-by-step explanation:
cos 68° + tan 76° = cos (90° - 22°) + tan(90° - 22°) + tan (90° - 14°)
= sin 22° + cot 14°
[cos (90° - θ) = sin θ and tan (90° - θ) = cot θ]
I think u have the answer.
Anyway hope it will help u.
Similar questions