Math, asked by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ, 2 months ago

Express cos 68° + tan 76° in terms of angles between 0 & 45​

Answers

Answered by tennetiraj86
19

Step-by-step explanation:

Given:-

cos 68° + tan 76°

To find:-

Express cos 68° + tan 76° in terms of angles between 0° & 45°

Solution:-

Given that : cos 68° + tan 76°

It can be written as

Cos (90°-22°) + Tan (90°- 14°)

We know that

Cos (90°-A) = Sin A

Tan (90°-A) = Cot A

So ,

Cos (90°-22°)= Sin 22°

Tan (90°-14°) = Cot 14°

Cos (90°-22°) + Tan (90°- 14°)

=>Sin 22° + Tan 14°

Answer:-

Cos 68°+ Tan 76° = Sin 22° + Cot 14°

Used formulae:-

  • Cos (90°-A) = Sin A
  • Tan (90°-A) = Cot A

Answered by ItzImperceptible
10

Step-by-step explanation:

cos 68° + tan 76° = cos (90° - 22°) + tan(90° - 22°) + tan (90° - 14°)

= sin 22° + cot 14°

[cos (90° - θ) = sin θ and tan (90° - θ) = cot θ]

I think u have the answer.

Anyway hope it will help u.

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