Question

Express cos 71° - sin 57° + tan 63° in terms of trignometric ratios of angles between 0° and 45°

Answer 1

Hiii. .....friend

the answer is here,

$= > \cos(71) - \sin(57) + \tan(63)$

$= > \: \cos(90 - 19) - \sin(90 - 33) + \tan(90 - 27)$
By using the formulas,

Cos (90-A) =SinA.

Sin (90-A) =CosA.

Tan (90-A) =CotA.

$= > \: \sin(19) - \cos(33) + \cot(27)$

:-)Hope it helps u.