Express cos 71° - sin 57° + tan 63° in terms of trigonometric ratios of angles between 0° and 45°.
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We know that sinA = cos(90-A) & cosA= sin(90-A)
Simiraly answer goes sin 19 - cos 33 +cot 27
Simiraly answer goes sin 19 - cos 33 +cot 27
Nayana665:
Its actually tan not cot :)
Its alright
but tanA = cot (90-A)
so answer goes like that
Thank you very much for that
U r welcome
Answered by
1
HEYA....✌✌✌✌
HERE IS YOUR ANSWER.......
Cos@=sin(90-@)
Cos71=sin(90-71)
===>>>sin19
Sin@=cos(90-@)
Sin59=cos(90-59)
===>>>>cos31
So sin19-cos31 is between 0° to 45°
Hence proved//
HOPE MY ANSWER WOULD HELP YOU
REGARD MADHU@
HERE IS YOUR ANSWER.......
Cos@=sin(90-@)
Cos71=sin(90-71)
===>>>sin19
Sin@=cos(90-@)
Sin59=cos(90-59)
===>>>>cos31
So sin19-cos31 is between 0° to 45°
Hence proved//
HOPE MY ANSWER WOULD HELP YOU
REGARD MADHU@
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