Question

express cos theta in terms of cot theta​

Answer 1

Answer:

Here's your answer

$\cot(theta) = \frac{ \cos(theta) }{ \sin(theta \: ) } \\ \\ \cot(theta) \times \sin(theta) = \cos(theta)$

Answer 2

Step-by-step explanation:

I have assumed theta =A

cot theta = 1/tan theta =1/√(tan^2A)

=1/√(1+sec^2A)

=1/√(1+1/cos^2A)

=cosA/√(1+cos^2A)