Question

express Cos2A/(1 - sin 2A) interm of tanA​

Answer 1

$\large \bold{ \frac{cos2 A}{1 -sin2 A } }$

$\large \bold{ = \frac{ \frac{cos2A}{cos2A} }{ \frac{1 - sin2A}{cos2A} }}$

$\large \bold{ = \frac{1}{ \frac{1}{cos2A} - \frac{sin2A}{cos2A} } }$

$= \frac{1}{sec2A -tan2A }$

$\large \bold{ = \frac{1}{ \sqrt{1 + ( tan2A )^{2} } - tan2A} }$