Question

express cos62°+ Sin 72° in
terms of tratios of
the angle between 0 and 45°
​

Answer 1

Answer:

sin28 + cos18

Step-by-step explanation:

From properties, sinA = cos(90 - A)

                            cosA = sin(90 - A)

So,

        cos62 = sin(90 - 62)

                   = sin28

         sin72 = cos(90 - 72)

                   = cos18

Hence,

⇒ cos62 + sin72

⇒ sin28 + cos18

Answer 2

ᎯᏁᏕᏯᎬᏒ

cos Ø = sin (90°- Ø)

cos 62° = sin (90°-62°)

cos 62° = sin 28° _______________(i)

sin Ø = cos (90° - Ø)

sin 72° = cos (90°-72°)

sin 72° = cos 18° _________________(ii)

cos 62°+ sin 72° = sin 28° + cos 18°