express cosec 48+tan88 in terms of t-ratios
Answers
Answered by
14
1/tan48+tan 48
1+tan48×tan48/tan48
cosec 48=1/tan 48
or
tan 48=1/cosec 48.
You can express both the values in any of the above ratios
1+tan48×tan48/tan48
cosec 48=1/tan 48
or
tan 48=1/cosec 48.
You can express both the values in any of the above ratios
Answered by
57
Hi !
I think your question is ,
Express cosec 48°+tan 88° in terms of t-ratios of angles between 0° and 45°
cosec 48° + tan 88°
we know that,
cosec 48° = sec (90 - 48)°
= sec 42°
also,
tan 88° = cot(90 - 88)°
= cot 2°
Hence ,
cosec 48° + tan 88° can be expressed as --->
sec 42° + cot 2°
Hope this helps you !
I think your question is ,
Express cosec 48°+tan 88° in terms of t-ratios of angles between 0° and 45°
cosec 48° + tan 88°
we know that,
cosec 48° = sec (90 - 48)°
= sec 42°
also,
tan 88° = cot(90 - 88)°
= cot 2°
Hence ,
cosec 48° + tan 88° can be expressed as --->
sec 42° + cot 2°
Hope this helps you !
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