Question

Express cot 85°+75° in terms of trignommetric ratios of angles between 0° and 45°​

Answer 1

$\\ \\ \bf cot~ 85°+ cot ~75° </p><p>\\ \\ \bf = cot~ (90° - 5°) + cos ~(90°-15°)</p><p>\\ \\ \bf = tan ~5° + sin ~15°$

Answer 2

$\\ \\ \sf cot~ 85°+ cot ~75° </p><p>\\ \\ \sf = cot~ (90° - 5°) + cos ~(90°-15°)</p><p>\\ \\ \sf = tan ~5° + sin ~15°$