Question

express cot A in terms of cosec A, Sin A and Sec A​

Answer 1

Answer:

An equation Involving trigonometric ratios of angle is called a trigonometry identity, if it is true for all values of the angles involved for any acute angle (A) we have 3 identities.

sin²A + cos²A= 1 1 + tan²A= sec²A cot²A+ 1 = cosec²A

Solution:

1)

sinA= 1/cosecA=1/√(1+cot²A)

[ cot²A+ 1 = cosec²A, cosecA= √( 1+cot²A)]

2)

tanA= 1/cotA

3)

secA= √(1+tan²A)

[sec²A= 1+tan²A, secA= √ (1+tan²A)]

secA= √(1+ (1/cot²A)) = √ (1+1/ cot²A) secA= √(cot²A+1/cot²A)

secA= √1+cot²A/ (cotA)