Question

Express
Cot teta in
terms
of
sec teta​

Answer 1

sec²thetha = 1 + tan²thetha

or sec²thetha - 1 = tan²thetha

or cot²thetha = 1/(sec²tetha - 1)

cot thetha = sqaure root of 1/(sec²thetha -1)

Answer 2

Answer:

Step-by-step explanation:

We know that 1 + tan²Ф = sec²Ф

So,

=>  1 + 1/cot²Ф = sec²Ф    [tan²Ф = 1/cot²Ф]

=>  1/cot²Ф = sec²Ф - 1

=>   cot²Ф = 1 / sec²Ф - 1

=>   cotФ = $\sqrt{1 / sec²Ф - 1}$  = $1 / \sqrt{sec²Ф - 1}$

Hope it helps

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