Question

express cot theta in terms of sin theta​

Answer 1

Answer:

cot theta = cos theta / sin theta

and cos theta can be written as √1-sin²theta

so cot theta = √1-sin²theta by sin theta

hope it helps u

Answer 2

Answer:

cot theta =$\frac{sin∅}{cos∅}$

and cos∅ can be written as $\sqrt{1-sinx^{2} ∅}$

so cot theta = $\frac{\sqrt{1-sinx^{2}∅ }}{sin∅}$

Hope this is helpful