Express cot theta into sin theta
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Hii There!!!
We know,![\bf{cotθ=cos θ/sinθ} \bf{cotθ=cos θ/sinθ}](https://tex.z-dn.net/?f=%5Cbf%7Bcot%CE%B8%3Dcos+%CE%B8%2Fsin%CE%B8%7D)
and![\bf{cos^2θ=1-sin^2θ} \bf{cos^2θ=1-sin^2θ}](https://tex.z-dn.net/?f=%5Cbf%7Bcos%5E2%CE%B8%3D1-sin%5E2%CE%B8%7D)
=> cos θ = ±√[1 - sin^2θ]
Therefore,
cotθ =±√[1-sin^2θ]/sinθ
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Hope it helps :)
We know,
and
=> cos θ = ±√[1 - sin^2θ]
Therefore,
cotθ =±√[1-sin^2θ]/sinθ
_______________________
⭐
Hope it helps :)
Abhisheksingh563:
hiii
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