Question

express each number as a product of its prime factors :
(1) 140
(2)156
(3)3825
(4)5005
(5)7429​

Answer 1

Answer:

Step-by-step explanation:

[1] 140 = 2*2*5*7 = 2² * 5*7

[2] 156 = 2 * 2 * 3 * 13 = 2² * 3*13

[3] 3825 = 3 * 3 * 5 * 5 * 17 = 3² * 5² * 13

[4] 5005 = 5 * 7 * 11 * 13 = 5 * 7* 11 * 13

[5] 7429 = 17 * 19 * 23 = 17 * 19 * 23

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

(i) 140

By Taking the LCM of 140, we will get the product of its prime factor.

Therefore,

• 140 = 2 × 2 × 5 × 7 × 1 = 22 × 5 × 7

(ii) 156

By Taking the LCM of 156, we will get the product of its prime factor.

Hence,

• 156 = 2 × 2 × 13 × 3 × 1 = 22 × 13 × 3

(iii) 3825

By Taking the LCM of 3825, we will get the product of its prime factor.

Hence,

• 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32 × 52 × 17

(iv) 5005

By Taking the LCM of 5005, we will get the product of its prime factor.

Hence,

• 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

(v) 7429

By Taking the LCM of 7429, we will get the product of its prime factor.

Hence,

• 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23