Express each number as a product of its prime factors:
(i) 140
(ii) 156
(iii) 3825
(iv) 5005
(v) 7429
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140 answer hope will help
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1)As now we have all prime factors, the process is complete and prime factors of 140 are 2×2×5×7
2) The prime factorization of 156 = 22•3•13.
3) Factorise 3825 as follows:3825=3×3×5×5×17=32×52×17Since, 3,5 and 17 are prime numbers as these are the numbers that are only divisible by themselves. Hence, 3825=32×52×17.
4)13 is one of the factors! The orange divisor(s) above are the prime factors of the number 5,005. If we put all of it together we have the factors 5 x 7 x 11 x 13 = 5,005. It can also be written in exponential form as 51 x 71 x 111 x 131.
5)Prime factors for 7429 is 17×19×23. So the prime factorisation for 7429 is 17×19×23.
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