Math, asked by srivathsun2002, 1 year ago

express each of following as product of powers of thier prime factors?

1]948

Answers

Answered by Shravani83
5
948 = 2 × 2 × 3 × 79
Expressing as power,
948 = 2² × 3¹ × 79¹

srivathsun2002: pls answer to my another question
Answered by kvnmurty
5
since 948 is even number,  units digit is 8 - divisible by 8 - it has a factor 2. The last two digits 48 - it is divisible by 4 => number is divisible by 4.  Sum of all digits is 21 So it is divisible by 3. 

948 = 2 * 2 * 3 * 79 
Now 79 seems to be prime... so stop.
2² * 3 * 79

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